从缓存的角度思考优化 发表于 2018-12-19 | 12345678910111213141516171819202122232425262728// 1 fib(100)function fib(n) { if (n <= 1) { return 1 } return fib(n-1) + fib(n-2)}// fib(100)// 2 fib2(100000)function fib2(n) { if (n <= 1) { return 1 } if (fib2[n]) { return fib2[n] } fib2[n] = fib2(n-1) + fib2(n-2) return fib2[n]}// 3 fib3(1000000)function fib3(n , f1 = 1 , f2 = 1) { if( n <= 1 ) { return f2 } return fib3(n - 1, f2, f1 + f2)}